85-(4x^2)=(x^2)+5x+25

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Solution for 85-(4x^2)=(x^2)+5x+25 equation:



85-(4x^2)=(x^2)+5x+25
We move all terms to the left:
85-(4x^2)-((x^2)+5x+25)=0
We get rid of parentheses
-4x^2-x^2-5x-25+85=0
We add all the numbers together, and all the variables
-5x^2-5x+60=0
a = -5; b = -5; c = +60;
Δ = b2-4ac
Δ = -52-4·(-5)·60
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-35}{2*-5}=\frac{-30}{-10} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+35}{2*-5}=\frac{40}{-10} =-4 $

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